How many milliliters of syrup are in a 100-ml sample containing 6.55 g of syrup per 20 mL if the syrup's specific gravity is 1.31?

Answer:25 millilitersStep-by-step explanation:Given:volume of sample = 100 mlSyrup present in sample = 6.55 g per 20 mLTherefore in 100 mL, amount of syrup present = [tex]\frac{\textup{6.55}}{\textup{20}}\times100[/tex] oramount of syrup present in 100 mL sample = 32.75 gramsNow, Specific gravity of the syrup = 1.31also, Specific gravity of the syrup = [tex]\frac{\textup{Density of syrup}}{\textup{Density of water}}[/tex] or1.31 = [tex]\frac{\textup{Density of syrup}}{\textup{1 g/mL}}[/tex] orDensity of syrup = 1.31 g/mLalso, Density = [tex]\frac{\textup{Mass}}{\textup{Volume}}[/tex] therefore, 1.31 = [tex]\frac{\textup{32.75}}{\textup{Volume of syrup in the sample}}[/tex] orVolume of syrup in the sample = [tex]\frac{\textup{32.75}}{\textup{1.31}}[/tex] orVolume of syrup in the sample = 25 milliliters