Q:

In the game of blackjack played with one deck, a player is initially dealt 2 diferent cards from the 52 different cards in the deck A winning ℡ack ack hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. The two cards can be in any order. Find the probability of being dealt a blackjack hand. What approximate percentage of hands are winning blackjack hands? The probability is □ Type an integer or a simplified fraction) The percentage of hands that are winning blackjack hands is Round to two decimal places as needed.)

Accepted Solution

A:
Answer:4.83%Step-by-step explanation:Total number of possible hands we are interested in selecting two of the 52 cards in the deck. n=52r=2therefore, 52C_2 = 52!/(2!50!)= 1326 possible hands therefore total number of blackjacks A blackjack consists of 1 of 4 aces and 1 of 16 other cards that are worth 10 points. by fundamental counting rule 4*16= 64 possible blackjacks2)% of hands that are winning blackjack hands =(32/663)*100 =4.83%