The value of p for which the lines 3x + y + 2 = 0, 2x - y + 3 = 0, and x+py = 3 are concurrent is​

Answer:Step-by-step explanation:the system is :  3x + y + 2 = 0.......(1)                           2x - y + 3 = 0......(2)                          x+ py - 3 = 0......(3)(1)+(2) : 3x+y+2 +2x-y+3 =0            5x+5 =0so : x = -1put x = -1 in equation (2) : 2(-1)-y+3 = 0so : y = 1the intersection point is A(-1 ; 1)put x = -1 and y = 1 in equation (3) : -1+p(1)-3 =0        so : p = 4sketch the line :3x + y + 2 = 0 and 2x - y + 3 = 0 and  x+ 4y - 3 = 0y = -3x-2 ...(color red)  and y=2x+3....(color blue) and  y = -1/4x +3/4...(color purple)