Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.The combined area of the lots is 1,848 square feet. How many feet wide is Lot B? Show Work!(A) 11 feet(B) 14 feet(C) 44 feet(D) 56 feet

Answer:The width of lot B is 11 feet, so option A is correct.Step-by-step explanation:Given:Two rectangular properties share a common side.   Lot A is 33 feet wide and 42 feet long.  The combined area of the lots = 1,848 square feet.  To find:How many feet wide is Lot B?  Solution:we know that, area of a rectangle is length x breadth Then area of lot A = 33 x 42 = 1386 square feet. And area of lot B = width x 42 Now, we are given that, total area = 1848   area of lot A + area of lot B = 1848   1386 + width x 42 = 1848   width x 42 = 1848 – 1386   width x 42 = 462  [tex]width =\frac{42}{462}[/tex] width = 11 Hence, the width of lot B is 11 feet, so option A is correct.